Honors Pre-Calculus

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Invertible Matrix

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Honors Pre-Calculus

Definition

An invertible matrix is a square matrix that has an inverse matrix. In other words, it is a matrix that can be multiplied by another matrix to produce the identity matrix, which means that the original matrix can be 'undone' or reversed.

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5 Must Know Facts For Your Next Test

  1. A matrix is invertible if and only if its determinant is non-zero.
  2. The inverse of an invertible matrix $A$ is denoted as $A^{-1}$, and satisfies the equation $A^{-1}A = AA^{-1} = I$, where $I$ is the identity matrix.
  3. If a matrix is not invertible, it is said to be singular, and its determinant is zero.
  4. Invertible matrices play a crucial role in solving systems of linear equations using the inverse method, as described in section 9.7.
  5. The inverse of a 2x2 matrix $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$ is $\frac{1}{ad-bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix}$.

Review Questions

  • Explain the relationship between the determinant of a matrix and its invertibility.
    • The determinant of a matrix is a key property that determines whether the matrix is invertible or not. A matrix is invertible if and only if its determinant is non-zero. If the determinant is zero, the matrix is said to be singular and it does not have an inverse. The determinant can be thought of as a measure of the 'size' or 'volume' of the matrix, and a non-zero determinant indicates that the matrix can be 'undone' or reversed.
  • Describe how invertible matrices are used to solve systems of linear equations, as discussed in section 9.7.
    • In section 9.7, the concept of invertible matrices is used to solve systems of linear equations. If a system of linear equations can be represented in matrix form as $Ax = b$, where $A$ is the coefficient matrix, $x$ is the vector of unknowns, and $b$ is the vector of constants, then the system can be solved by multiplying both sides by the inverse of $A$, denoted as $A^{-1}$. This gives $x = A^{-1}b$, which provides the unique solution to the system, provided that $A$ is invertible (i.e., its determinant is non-zero).
  • Explain how to find the inverse of a 2x2 matrix, and discuss the significance of this result.
    • The inverse of a 2x2 matrix $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$ can be calculated using the formula $\frac{1}{ad-bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix}$. This formula shows that the inverse of a 2x2 matrix depends on the determinant of the matrix, $ad-bc$. If this determinant is non-zero, then the matrix is invertible, and the inverse can be used to solve systems of linear equations involving 2 variables. The ability to easily compute the inverse of a 2x2 matrix is an important result that simplifies the process of solving systems of linear equations in this context.
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