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key term - $x = x_0 + v_0t + \frac{1}{2}at^2$

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Definition

$x = x_0 + v_0t + \frac{1}{2}at^2$ is a fundamental equation in physics that describes the position of an object as a function of time, given its initial position ($x_0$), initial velocity ($v_0$), and constant acceleration ($a$). This equation is used to represent the motion of an object under constant acceleration, such as the motion of a falling object or the motion of an object under the influence of a constant force.

5 Must Know Facts For Your Next Test

  1. The equation $x = x_0 + v_0t + \frac{1}{2}at^2$ is derived from the definition of velocity ($v = \frac{\Delta x}{\Delta t}$) and the constant acceleration formula ($a = \frac{\Delta v}{\Delta t}$).
  2. This equation can be used to describe the motion of an object in one dimension, such as the vertical motion of a falling object or the horizontal motion of a projectile.
  3. The term $\frac{1}{2}at^2$ represents the distance traveled due to the constant acceleration, while $v_0t$ represents the distance traveled due to the initial velocity.
  4. The equation is valid only for constant acceleration, meaning the acceleration of the object does not change over time.
  5. The equation can be rearranged to solve for other variables, such as velocity ($v = v_0 + at$) or acceleration ($a = \frac{v - v_0}{t}$).

Review Questions

  • Explain how the terms in the equation $x = x_0 + v_0t + \frac{1}{2}at^2$ represent the motion of an object.
    • The equation $x = x_0 + v_0t + \frac{1}{2}at^2$ describes the position of an object at time $t$ as the sum of three terms. The first term, $x_0$, represents the object's initial position. The second term, $v_0t$, represents the distance traveled due to the object's initial velocity. The third term, $\frac{1}{2}at^2$, represents the distance traveled due to the object's constant acceleration. Together, these three terms fully describe the object's position at any given time under constant acceleration.
  • Discuss how the equation $x = x_0 + v_0t + \frac{1}{2}at^2$ can be used to analyze the motion of a falling object near the Earth's surface.
    • When analyzing the motion of a falling object near the Earth's surface, the equation $x = x_0 + v_0t + \frac{1}{2}at^2$ can be used. In this case, the initial position $x_0$ would represent the object's starting height, the initial velocity $v_0$ would be the object's initial downward velocity (which is often zero), and the acceleration $a$ would be the acceleration due to gravity, which is approximately $-9.8$ m/s^2. By plugging in these values and solving the equation, one can determine the object's position at any given time during its fall, which is useful for understanding the kinematics of falling objects.
  • Evaluate how the equation $x = x_0 + v_0t + \frac{1}{2}at^2$ can be used to model the motion of a projectile launched with an initial velocity and angle.
    • The equation $x = x_0 + v_0t + \frac{1}{2}at^2$ can be used to model the motion of a projectile launched with an initial velocity and angle by considering the horizontal and vertical components of the motion separately. In the horizontal direction, the acceleration $a$ would be zero, and the equation would simplify to $x = x_0 + v_0t$, which describes the horizontal distance traveled. In the vertical direction, the acceleration $a$ would be the acceleration due to gravity, $-9.8$ m/s^2, and the equation would describe the vertical position of the projectile. By combining the horizontal and vertical motions, the full trajectory of the projectile can be modeled using this equation.