Intermediate Algebra

📘Intermediate Algebra Unit 2 – Solving Linear Equations

Linear equations are the building blocks of algebra, representing straight lines on graphs. They follow the form ax + b = c, where a, b, and c are constants and x is the variable. Solving these equations is crucial for various fields and lays the groundwork for more complex algebraic concepts. Understanding linear equations involves key concepts like variables, coefficients, and constants. The solving process uses inverse operations to isolate variables. Real-world applications include calculating costs, determining work rates, and finding break-even points in business. Mastering this skill opens doors to more advanced mathematical topics.

What's This All About?

  • Linear equations represent a straight line on a graph and have the general form ax+b=cax + b = c, where aa, bb, and cc are constants and xx is the variable
  • Solving linear equations involves finding the value of the variable that makes the equation true
  • Linear equations can have one solution (x=3x = 3), no solution (0=10 = 1), or infinitely many solutions (2x=2x2x = 2x)
  • Solving linear equations is a fundamental skill in algebra and is used in various fields, such as physics, engineering, and economics
  • Understanding how to solve linear equations is essential for more advanced topics in algebra, such as systems of equations and inequalities

Key Concepts You Need to Know

  • Variables represent unknown values in an equation, usually denoted by letters like xx, yy, or zz
  • Coefficients are the numbers that multiply the variables in an equation (2x2x, where 22 is the coefficient)
  • Constants are the numbers in an equation that are not multiplied by a variable (x+3x + 3, where 33 is the constant)
  • Like terms are terms that have the same variable raised to the same power (2x2x and 3x3x are like terms)
  • The equality sign (==) indicates that the expressions on both sides of the equation have the same value
  • Inverse operations are used to isolate the variable and solve the equation (addition and subtraction, multiplication and division)
    • To undo addition, subtract the same value from both sides of the equation
    • To undo subtraction, add the same value to both sides of the equation
    • To undo multiplication, divide both sides of the equation by the same value
    • To undo division, multiply both sides of the equation by the same value

Breaking Down Linear Equations

  • Identify the variable, coefficients, and constants in the equation
  • Combine like terms on each side of the equation by adding or subtracting their coefficients (2x+3x=5x2x + 3x = 5x)
  • Use the distributive property to remove parentheses when necessary (2(x+3)=2x+62(x + 3) = 2x + 6)
  • Isolate the variable by performing the same operation on both sides of the equation
    • Add or subtract constants to get the variable terms on one side and the constant terms on the other side (2x+3=72x + 3 = 7 becomes 2x=42x = 4)
    • Divide both sides by the coefficient of the variable to solve for the variable (2x=42x = 4 becomes x=2x = 2)
  • Check your solution by substituting the value back into the original equation to ensure it makes the equation true

Step-by-Step Solving Methods

  • Simplify each side of the equation by combining like terms and using the distributive property
  • Add or subtract constants to isolate the variable terms on one side of the equation
  • Add or subtract variable terms to get all variable terms on one side of the equation
  • Divide both sides of the equation by the coefficient of the variable to solve for the variable
  • Check your solution by substituting the value back into the original equation
  • Example: Solve 2(3x1)+4x=5x+82(3x - 1) + 4x = 5x + 8
    • Simplify: 6x2+4x=5x+86x - 2 + 4x = 5x + 8
    • Combine like terms: 10x2=5x+810x - 2 = 5x + 8
    • Subtract 5x5x from both sides: 5x2=85x - 2 = 8
    • Add 22 to both sides: 5x=105x = 10
    • Divide both sides by 55: x=2x = 2
    • Check: 2(3(2)1)+4(2)=5(2)+82(3(2) - 1) + 4(2) = 5(2) + 8 simplifies to 14=1414 = 14, so the solution is correct

Common Pitfalls and How to Avoid Them

  • Forgetting to distribute when removing parentheses can lead to incorrect simplification
    • Always use the distributive property when removing parentheses (2(x+3)=2x+62(x + 3) = 2x + 6, not 2x+32x + 3)
  • Subtracting a negative number is the same as adding a positive number
    • Be careful with signs when subtracting negative terms (x(3)=x+3x - (-3) = x + 3)
  • Dividing by a negative coefficient will change the direction of the inequality sign
    • When solving inequalities, if you divide by a negative number, reverse the inequality sign (2x<6-2x < 6 becomes x>3x > -3)
  • Checking your solution is crucial to ensure you haven't made any mistakes along the way
    • Always substitute your solution back into the original equation to verify its correctness

Real-World Applications

  • Calculating the cost of items based on quantity and price per unit (5x+10=605x + 10 = 60, where xx is the number of items and 6060 is the total cost)
  • Determining the time required to complete a task based on the rate of work and the amount of work done (2x+3=152x + 3 = 15, where xx is the number of hours worked)
  • Finding the break-even point in a business, where revenue equals costs (500x=2000+100x500x = 2000 + 100x, where xx is the number of units sold)
  • Balancing chemical equations in chemistry (2H2+O2=2H2O2H_2 + O_2 = 2H_2O)
  • Solving for an unknown dimension in geometry problems (2x+3=152x + 3 = 15, where xx is the length of a side of a rectangle)

Practice Problems and Tips

  • Practice solving linear equations with various levels of difficulty to build your skills and confidence
  • Start with simple equations and gradually progress to more complex ones
  • Pay attention to the signs of the terms and coefficients, as they can affect the direction of the inequality sign when solving inequalities
  • Double-check your work by substituting your solution back into the original equation
  • Example: Solve 3(2x1)4(x+2)=5x73(2x - 1) - 4(x + 2) = 5x - 7
    • Simplify: 6x34x8=5x76x - 3 - 4x - 8 = 5x - 7
    • Combine like terms: 2x11=5x72x - 11 = 5x - 7
    • Subtract 2x2x from both sides: 11=3x7-11 = 3x - 7
    • Add 77 to both sides: 4=3x-4 = 3x
    • Divide both sides by 33: 43=x-\frac{4}{3} = x
    • Check: 3(2(43)1)4((43)+2)=5(43)73(2(-\frac{4}{3}) - 1) - 4((-\frac{4}{3}) + 2) = 5(-\frac{4}{3}) - 7 simplifies to 7=7-7 = -7, so the solution is correct

Beyond Basic Linear Equations

  • Linear equations can be extended to include absolute value expressions (2x3=7|2x - 3| = 7)
  • Systems of linear equations involve solving two or more linear equations simultaneously to find the values of multiple variables
  • Inequalities are similar to equations but use inequality signs (<<, >>, \leq, \geq) instead of the equality sign (==)
  • Graphing linear equations and inequalities can help visualize the solution sets and understand the relationships between variables
  • More advanced topics in algebra, such as quadratic equations and exponential functions, build upon the foundational skills of solving linear equations


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© 2024 Fiveable Inc. All rights reserved.
AP® and SAT® are trademarks registered by the College Board, which is not affiliated with, and does not endorse this website.